Question

Mr(MgSo4)= Mr(Al2(Co3)3)=

Answer 1

Mr(MgSO4) = 24+32+16*4 = 120  г/моль

Mr(Al2(CO3)3) = 26*2+3*(12+16*3) = 232 г/моль

Answer 2

To find the molar mass (Mr) of a compound, you need to add up the atomic masses of all the atoms in the chemical formula.

1. Magnesium sulfate (MgSO4):

• Magnesium (Mg) has a molar mass of approximately 24.305 g/mol.
• Sulfur (S) has a molar mass of approximately 32.06 g/mol.
• Oxygen (O) has a molar mass of approximately 16.00 g/mol. Adding them up: 24.305 + 32.06 + 4 * 16.00 = 24.305 + 32.06 + 64.00 = 120.365 g/mol.

So, the molar mass of MgSO4 (Magnesium sulfate) is approximately 120.365 g/mol.

2. Aluminum carbonate (Al2(CO3)3):

• Aluminum (Al) has a molar mass of approximately 26.98 g/mol.
• Carbon (C) has a molar mass of approximately 12.01 g/mol.
• Oxygen (O) has a molar mass of approximately 16.00 g/mol. Adding them up: 2 * 26.98 + 3 * (12.01 + 3 * 16.00) = 2 * 26.98 + 3 * (12.01 + 48.00) = 2 * 26.98 + 3 * 60.01 = 53.96 + 180.03 = 234.99 g/mol.

So, the molar mass of Al2(CO3)3 (Aluminum carbonate) is approximately 234.99 g/mol.

To summarize:

• Molar mass of MgSO4 (Magnesium sulfate): approximately 120.365 g/mol.
• Molar mass of Al2(CO3)3 (Aluminum carbonate): approximately 234.99 g/mol.