Question

Решить: CoO + H2O = FeO + H2O = H2O + Na2O = BaO + H2O =

Answer 1

CoO + H₂O - реакция не идёт

FeO + H₂O - реакция не идёт

H₂O + Na₂O -> 2NaOH

BaO + H₂O -> Ba(OH)₂

Answer 2

To solve this chemical equation, we need to balance it properly. The goal is to ensure that the same number of each type of atom appears on both sides of the equation. Let's balance each reaction one by one:

1. CoO + H2O = FeO + H2O

To balance the equation, we can see that there is only one oxygen (O) atom on each side. To balance hydrogen (H) atoms, add a coefficient of 2 in front of the water (H2O) on the left side:

CoO + 2H2O = FeO + H2O

Now, the hydrogen atoms are balanced (2 on both sides), but the oxygen atoms are not. Counting oxygen atoms, we have:

1 on the left (from CoO) + 2 on the left (from H2O) = 3 oxygen atoms on the left side.

1 on the right (from FeO) + 1 on the right (from H2O) = 2 oxygen atoms on the right side.

To balance oxygen atoms, add a coefficient of 1/2 in front of FeO on the right side:

CoO + 2H2O = (1/2)FeO + H2O

Now the equation is balanced for the first reaction.

2. FeO + H2O = H2O + Na2O

In this equation, we can see that water (H2O) appears on both sides. This means we can cancel it out:

FeO + H2O = Na2O

3. Na2O is already balanced because there is one Na (sodium) atom and one O (oxygen) atom on each side.

4. Na2O + H2O = BaO + H2O

Similar to the previous situation, water (H2O) appears on both sides, so we can cancel it out:

Na2O = BaO

Now, the equation is balanced for all reactions:

1. CoO + 2H2O = (1/2)FeO + H2O
2. FeO + H2O = Na2O
3. Na2O
4. Na2O = BaO

Note: It's important to mention that the initial equation you provided has some redundancies and is not standard. Each chemical equation should represent a specific reaction, and the products of one reaction should not appear as reactants in another. In this case, some compounds (like H2O and Na2O) appear multiple times, making it unconventional. Nonetheless, I have balanced the equations based on what you provided.