Question

Бутин-1+2 моль Br2----

Answer 1

образуется 11,22 тетрабромбутан, поскольку участвует 2 моля брома.

CH≡C-CH2-CH3 + 2Br2 = CH(Br)2 - C(Br)2 - CH2-CH3

Answer 2

To balance the chemical equation for the reaction between butene (C4H8) and bromine (Br2), we first need to write the unbalanced equation:

C4H8 + Br2 → ?

Now, let's balance the equation step by step:

1. Balance the carbon atoms: There are four carbon atoms on the left side (C4H8) and only one carbon atom on the right side (C). To balance the carbons, we need to place a coefficient of 4 in front of the bromine on the right side:

C4H8 + 4 Br2 → ?

2. Balance the hydrogen atoms: There are eight hydrogen atoms on the left side (C4H8) and only two hydrogen atoms on the right side (2 H). To balance the hydrogens, we need to place a coefficient of 4 in front of the water (H2O) on the right side:

C4H8 + 4 Br2 → 4 H2O + ?

3. Balance the bromine atoms: There are four bromine atoms on the left side (4 Br2) and only four bromine atoms on the right side (4 Br2). The bromine atoms are already balanced.

The balanced equation is:

C4H8 + 4 Br2 → 4 H2O + 4 HBr

This balanced equation represents the reaction between 1 mole of butene (C4H8) and 2 moles of bromine (Br2), resulting in the formation of 4 moles of water (H2O) and 4 moles of hydrogen bromide (HBr).