Question

CuO+H2=Cu+H2O. m(H2)=1.7 гр m(Cu)-? СРОЧНО!!​

Answer 1

Ответ во вложении. Удачки)

Answer 2

Ответ:

решение смотрите на фото

Объяснение:

Answer 3

To balance the chemical equation and determine the mass of copper (Cu) produced when reacting with 1.7 grams of hydrogen gas (H2) in the given reaction:

CuO + H2 = Cu + H2O

First, we need to balance the equation:

CuO + H2 = Cu + H2O

To balance the hydrogen atoms on both sides, we need two hydrogen molecules (H2) on the left side:

CuO + 2H2 = Cu + H2O

Now let's balance the oxygen atoms. There is one oxygen atom in CuO and one oxygen atom in H2O. So, we need to put a coefficient of 2 in front of CuO:

2CuO + 2H2 = Cu + H2O

Now the equation is balanced.

Now, let's calculate the molar masses:

• molar mass of H2 = 2 g/mol
• molar mass of Cu = 63.55 g/mol

Since 2 moles of hydrogen gas (H2) react with 1 mole of copper oxide (CuO) to produce 1 mole of copper (Cu), we can set up a ratio:

2 moles of H2 : 1 mole of Cu = 1.7 grams of H2 : x grams of Cu

Now, let's solve for x (the mass of copper):

x grams of Cu = (1.7 grams of H2 * 1 mole of Cu) / (2 moles of H2)

x grams of Cu = (1.7 g * 1 mol) / 2

x grams of Cu = 0.85 grams

So, the mass of copper (Cu) produced in the reaction is 0.85 grams.