Question

K2Cr2O7+HCl=CrCl3+KCl+Cl+H2O

Answer 1

Ответ:

Это окислительно-восстановительная (редокс) реакция:

6 Cl-I - 6 e- → 6 Cl0

(окисление)

2 CrVI + 6 e- → 2 CrIII

(восстановле́ние)

Answer 2

The chemical equation you provided is not balanced. I'll help you balance it using the oxidation state method.

First, let's write down the unbalanced equation: K2Cr2O7 + HCl = CrCl3 + KCl + Cl2 + H2O

Now, let's balance the elements one by one:

1. Balance oxygen (O) atoms: There are 7 oxygen atoms on the left side and only 1 oxygen atom on the right side. We can balance them by adding water (H2O) to the right side.

K2Cr2O7 + HCl = CrCl3 + KCl + Cl2 + 7H2O

2. Balance hydrogen (H) atoms: There are 2 hydrogen atoms on the left side (from HCl) and 14 hydrogen atoms on the right side (from 7H2O). We can balance them by adding HCl on the right side.

K2Cr2O7 + 14HCl = CrCl3 + KCl + Cl2 + 7H2O

3. Balance potassium (K) atoms: There are 2 potassium atoms on the left side (from K2Cr2O7) and 1 potassium atom on the right side (from KCl). We can balance them by adding one more KCl on the right side.

K2Cr2O7 + 14HCl = CrCl3 + 2KCl + Cl2 + 7H2O

4. Balance chromium (Cr) atoms: There are 2 chromium atoms on the left side (from K2Cr2O7) and 1 chromium atom on the right side (from CrCl3). We can balance them by adding another CrCl3 on the right side.

K2Cr2O7 + 14HCl = 2CrCl3 + 2KCl + Cl2 + 7H2O

5. Balance chlorine (Cl) atoms: There are 7 chlorine atoms on the left side (from K2Cr2O7 and HCl) and 2 chlorine atoms on the right side (from 2CrCl3 and KCl). We can balance them by adjusting the coefficient of Cl2 on the right side.

K2Cr2O7 + 14HCl = 2CrCl3 + 2KCl + 7Cl2 + 7H2O

Now the equation is balanced. The final balanced chemical equation is: K2Cr2O7 + 14HCl = 2CrCl3 + 2KCl + 7Cl2 + 7H2O