Question

M/Zn) = 132 CI2 ——————- V(Cl2)-? v(ZnCl2)-? m(ZnCl2)-?

Answer 1

Ответ:

Объяснение:

132 г           Х л, Х моль, Хг

 Zn       +       Cl2     =        ZnCl2

n=1 моль         n=1 моль

М=65 г/моль  М = 71 г/моль

m=65 г             m=71 г

132 г  Zn   -   Х г   Cl2

65 г  Zn    -  71 г   Cl2

m(Cl2) = 132 *71 | 65 = 144 г

n(Cl2) = m / M = 144 / 71 =2 моль

V(Cl2) = Vm *n = 22,4 * 2 = 44,8 л

Answer 2

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the reaction. Let's balance the given chemical equation:

CI2 + V(Cl2) → V(ZnCl2) + M(ZnCl2)

We know that the molar mass of CI2 (chlorine gas) is approximately 71 g/mol.

Given that M/Zn (molar mass of zinc) is 132 g/mol, we can calculate the molar mass of ZnCl2 (zinc chloride):

Molar mass of ZnCl2 = (M/Zn) + 2 * (molar mass of CI2) Molar mass of ZnCl2 = 132 + 2 * 71 Molar mass of ZnCl2 = 132 + 142 Molar mass of ZnCl2 = 274 g/mol

Now, let's balance the equation:

1 CI2 + 1 V(Cl2) → 1 V(ZnCl2) + 1 M(ZnCl2)

The balanced chemical equation is:

CI2 + V(Cl2) → V(ZnCl2) + M(ZnCl2)

So, the coefficients are: CI2 = 1 V(Cl2) = 1 V(ZnCl2) = 1 M(ZnCl2) = 1

Therefore, the balanced chemical equation is:

CI2 + V(Cl2) → V(ZnCl2) + M(ZnCl2)