Question

Урівняти за допомогою коефіцієнтів запропоновані рівняння 1. F2 + S →SF6 2. Al + S → Al2S3 3. Zn + O2 → ZnO 4. Ba+ HBr → BaBr2+ H25. Ca + O2 → CaO 6. Cr + S → Cr2S3 7. Mg + HCl → MgCl2+ H2 8. Al + Cl2 → AlCl3 9. О2 + NO → NO210. Fe(OH)3 → Fe2O3 + H2O 11. О2 + NO2 + H2O → HNO3 12. As2O5 + H2O → H3AsO413. КOH + H3PO4 → К3PO4 + H2O 14. Сr2O3 + HNO3 → Cr(NO3 )3 + H2O 15. P + O2 → P2O3 16. Na + O2 → Na2O 17. Na2O + P2O5 → Na3PO4 18. Al(OН)3 + HI → AlI3 + H2O 19. Li + H2O → LiOH + H220. NaOH + AlBr3→ Al(OH)3 + NaBr 21. Fe2O3 + HBr → FeBr3 + H2O 22. Al2(SO4)3 + BaCl2 → BaSO4 + AlCl323. C4H10 + O2 → CO2 + H2O 24. C6H5NH2 + O2 → CO2 + H2O + N2​

Answer 1

Объяснение:

урівняти за допомогою коефіцієнтів запропоновані рівняння

1. 3F2 + S →SF6

2. 2Al + 3S → Al2S3

3. 2Zn + O2 → 2ZnO

4. Ba+ 2HBr → BaBr2+ H2

5. 2Ca + O2 →2 CaO

6. 2Cr + 3S → Cr2S3

7. Mg + 2HCl → MgCl2+ H2

8. 2Al + 3Cl2 → 2AlCl3

9. О2 + 2NO → 2NO2

10. 2Fe(OH)3 → Fe2O3 + 3H2O

11. О2 + 4NO2 + 2H2O → 4HNO3

12. As2O5 + 3H2O → 2H3AsO4

13. 3КOH + H3PO4 → К3PO4 + 2H2O

15. 2P + 3O2 → 2P2O3

16. 4Na + O2 → 2Na2O

17. 3Na2O + P2O5 →2 Na3PO4

18. 2Al(OН)3 + 3HI → 2AlI3 + 3H2O

19. 2Li + 2H2O → 2LiOH + H2

20. 3NaOH + AlBr3→ Al(OH)3 +3 NaBr

21. Fe2O3 + 6HBr → 2FeBr3 + 3H2O

22. Al2(SO4)3 + 3BaCl2 → 3BaSO4 + 2AlCl3

23. 2C4H10 + 13O2 → 8CO2 + 10H2O

Answer 2

To balance the given chemical equations, we need to ensure that the number of atoms of each element on both sides of the equation is the same. We can do this by adjusting the coefficients in front of each compound. Let's balance the equations one by one:

1. F2 + S → SF6 1 F2 + 3 S → SF6

2. Al + S → Al2S3 2 Al + 3 S → Al2S3

3. Zn + O2 → ZnO 2 Zn + O2 → 2 ZnO

4. Ba + HBr → BaBr2 + H2 1 Ba + 2 HBr → 1 BaBr2 + 1 H2

5. Ca + O2 → CaO 2 Ca + O2 → 2 CaO

6. Cr + S → Cr2S3 4 Cr + 3 S → 2 Cr2S3

7. Mg + HCl → MgCl2 + H2 1 Mg + 2 HCl → 1 MgCl2 + 1 H2

8. Al + Cl2 → AlCl3 2 Al + 3 Cl2 → 2 AlCl3

9. O2 + NO → NO2 2 O2 + 2 NO → 2 NO2

10. Fe(OH)3 → Fe2O3 + H2O 2 Fe(OH)3 → 1 Fe2O3 + 3 H2O

11. O2 + NO2 + H2O → HNO3 3 O2 + 4 NO2 + 2 H2O → 4 HNO3

12. As2O5 + H2O → H3AsO4 1 As2O5 + 3 H2O → 2 H3AsO4

13. KOH + H3PO4 → K3PO4 + H2O 3 KOH + H3PO4 → K3PO4 + 3 H2O

14. Cr2O3 + HNO3 → Cr(NO3)3 + H2O 1 Cr2O3 + 6 HNO3 → 2 Cr(NO3)3 + 3 H2O

15. P + O2 → P2O3 4 P + 5 O2 → 2 P2O3

16. Na + O2 → Na2O 4 Na + O2 → 2 Na2O

17. Na2O + P2O5 → Na3PO4 2 Na2O + P2O5 → 2 Na3PO4

18. Al(OH)3 + HI → AlI3 + H2O 1 Al(OH)3 + 3 HI → 1 AlI3 + 3 H2O

19. Li + H2O → LiOH + H2 2 Li + 2 H2O → 2 LiOH + 1 H2

20. NaOH + AlBr3 → Al(OH)3 + NaBr 6 NaOH + 1 AlBr3 → 1 Al(OH)3 + 3 NaBr

21. Fe2O3 + HBr → FeBr3 + H2O 1 Fe2O3 + 6 HBr → 2 FeBr3 + 3 H2O

22. Al2(SO4)3 + BaCl2 → BaSO4 + AlCl3 1 Al2(SO4)3 + 3 BaCl2 → 3 BaSO4 + 2 AlCl3

23. C4H10 + 13 O2 → 4 CO2 + 5 H2O (Balancing organic reactions typically involves a more complex process, but this balanced equation is provided)

24. C6H5NH2 + 7 O2 → 6 CO2 + 3 H2O + N2 (Balancing organic reactions typically involves a more complex process, but this balanced equation is provided)

Please note that the coefficients in front of each compound represent the number of molecules or moles needed to balance the equation. These coefficients are meant to be whole numbers, and if fractions are present, they can be multiplied throughout the entire equation to obtain whole numbers.