Question

Al ⟶ AlCl3 ⟶ Na[Al(OH)4] ⟶ Al(OH)3 ⟶ Al2(SO4)3.​

Answer 1

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Answer 2

The sequence you provided shows a series of chemical reactions involving aluminum (Al) and various chemical compounds. Let's break down each reaction:

1. Al ⟶ AlCl3: This is a single displacement reaction where aluminum (Al) reacts with chlorine gas (Cl2) to form aluminum chloride (AlCl3).

2. AlCl3 ⟶ Na[Al(OH)4]: This reaction involves aluminum chloride (AlCl3) reacting with sodium hydroxide (NaOH) to form sodium tetrahydroxoaluminate [Na[Al(OH)4]].

3. Na[Al(OH)4] ⟶ Al(OH)3: In this reaction, sodium tetrahydroxoaluminate [Na[Al(OH)4]] decomposes to produce aluminum hydroxide (Al(OH)3).

4. Al(OH)3 ⟶ Al2(SO4)3: Finally, aluminum hydroxide (Al(OH)3) reacts with sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3).

The overall chemical equation for the entire sequence of reactions is as follows:

Al + 3 Cl2 ⟶ AlCl3 AlCl3 + 3 NaOH ⟶ Na[Al(OH)4] + 3 NaCl Na[Al(OH)4] ⟶ Al(OH)3 + NaOH 2 Al(OH)3 + 3 H2SO4 ⟶ Al2(SO4)3 + 6 H2O

Please note that the actual reaction conditions, such as temperature, pressure, and concentration, can influence the outcome of these reactions.