Question

Dano.AI+O3 m(AI2O3) =204 г. найти mAI ​

Answer 1

2Al+O3=Al2O3
n(Al2O3)=204г/102г\моль=2моль
n(Al)=2n(Al2O3)=4моль
m(Al)=4 моль *27г/моль=108г

Answer 2

To find the molar mass of AI (aluminum), we need to know the molar mass of the other two compounds involved in the reaction.

The balanced chemical equation is: 2 Al + 3 O2 -> 2 Al2O3

From the balanced equation, we can see that the stoichiometric ratio between AI (Aluminum) and AI2O3 (Aluminum Oxide) is 2:1.

Given that the molar mass of AI2O3 (Aluminum Oxide) is 204 g/mol, we can now find the molar mass of AI (Aluminum):

Molar mass of Al = (Molar mass of Al2O3) / 2 Molar mass of Al = 204 g/mol / 2 Molar mass of Al = 102 g/mol

So, the molar mass of AI (Aluminum) is 102 g/mol.