Question

V (H2) = 4,48лHCl; Vm=22л/мольm (Zn)- ?​

Answer 1

Ответ:

13 г

Объяснение:

2HCl+Zn=ZnCl2+H2

         0,2             0,2

n(H2)=V/Vm=4,48/22,4=0,2 моль

m(Zn)=n*M=0,2*65=13 г

Answer 2

To calculate the molar mass of zinc (Zn), we need more information than what you've provided. The equation you've given involves the volume of hydrochloric acid (HCl), but it doesn't provide any information about the reaction or the molar ratio between HCl and Zn.

If you can provide additional details about the reaction or the molar ratio, I can help you calculate the molar mass of zinc.