Question

CH3 - CH2 - CH2 - CH3 + Br2/hv ---- x1 + NaOH ------ x2 + Na ------- x3

Answer 1

Ответ:

Объяснение:

CH3 - CH2 - CH2 - CH3 + Br2/hv ---- H3C-CH2-C (Br) (CH3) - CH3 (X1) + HBr;

H3C-CH2-C (Br) (CH3) - CH3 (X1) +NaOH = H3C-CH2-C (OH) (CH3) - CH3 (X2) + NaBr;

2H3C-CH2-C (Br) (CH3) - CH3 + 2Na = H3C-CH2-C (CH3) 2-C (CH3) 2-CH2-CH3 (X3) + 2NaBr;

Answer 2

The reaction you provided is a multi-step process involving bromination and subsequent reactions with NaOH and Na. Here's a breakdown of the steps:

Step 1: Bromination of CH3-CH2-CH2-CH3 (butane) with Br2/hv When butane (CH3-CH2-CH2-CH3) reacts with bromine (Br2) in the presence of light (hv), a substitution reaction occurs. One of the hydrogen atoms in butane is replaced by a bromine atom (Br). The reaction can proceed as follows:

CH3-CH2-CH2-CH3 + Br2/hv → CH3-CH2-CH2-CH2Br + HBr

Step 2: Reaction with NaOH (Sodium Hydroxide) The bromoalkane (CH3-CH2-CH2-CH2Br) obtained in step 1 can undergo a reaction with sodium hydroxide (NaOH). This reaction is known as nucleophilic substitution, where the hydroxide ion (OH-) replaces the bromine atom. The reaction can be represented as:

CH3-CH2-CH2-CH2Br + NaOH → CH3-CH2-CH2-CH2OH + NaBr

Step 3: Reaction with Na (Sodium) The primary alcohol (CH3-CH2-CH2-CH2OH) formed in step 2 can undergo oxidation when treated with sodium (Na). The reaction with sodium results in the removal of a hydrogen atom from the alcohol, leading to the formation of an alkoxide ion (CH3-CH2-CH2-CH2O-) and hydrogen gas (H2). The reaction can be represented as:

CH3-CH2-CH2-CH2OH + 2Na → CH3-CH2-CH2-CH2O- + Na+ + H2

Note: It's important to remember that the given reaction sequence is a simplified representation, and the actual reaction conditions and mechanisms may vary depending on the specific reaction conditions and reagents used.