Question

M(Na)= 46 г.V(H2)-? 2Na+H2SO4=Na2SO4+H2​

Answer 1

Ответ:

Объяснение:

  46 г                                                           Х л

 2Na     +    H2SO4    =     Na2SO4     +    H2

n=2 моль                                                   n=1 моль

М=23 г/моль                                            Vm=22,4 л/моль

m=46 г                                                        V = 22,4 л

46 г  Na   -   Х л  Н2

46 г  Na   -  22,4 л  Н2

V(H2) = 46 * 22,4 / 46 = 22,4 л

Answer 2

The chemical equation provided is a balanced equation for the reaction between sodium (Na) and sulfuric acid (H2SO4) to form sodium sulfate (Na2SO4) and hydrogen gas (H2). The balanced equation is:

$2Na + H_2SO_4 \rightarrow Na_2SO_4 + H_2.$

The molar mass of sodium (Na) is $46 \, \text{g/mol}$. To find the volume of hydrogen gas produced ($V(H_2)$), you need to know the conditions under which the reaction occurs, particularly the temperature and pressure, because the volume of a gas is highly dependent on these factors.

Additionally, you can use the ideal gas law equation to calculate the volume of hydrogen gas produced if you know the amount of hydrogen gas produced in moles ($n$), the gas constant ($R$), the temperature ($T$), and the pressure ($P$).

$PV = nRT.$

Where:

• $P$ is the pressure of the gas in atmospheres (atm).
• $V$ is the volume of the gas in liters (L).
• $n$ is the number of moles of the gas.
• $R$ is the ideal gas constant, approximately $0.0821 \, \text{atm} \cdot \text{L/mol} \cdot \text{K}$.
• $T$ is the temperature in Kelvin (K).

If you provide the number of moles of hydrogen gas formed ($n$), the temperature, and the pressure, I can help you calculate the volume of hydrogen gas produced.