Question

Хлорид неизвестного элемента X, жидкий при 20 градусах, хлорид реагирует с водой с образованием белого пара, раствор обладает кислотными свойствами. Определите элемент. 1) В какой подгруппе находится неизвестный элемент X: 1,2 или 4?2) Какова реакция между X и водой? Изобразите тип реакции в целом3) Какова природа белого пара, образующегося при реакции X с водой?

Answer 1

Ответ:

PCl5 - хлорид фосфора

1)оно должно находится в пятой группе

2)PCl5+4H2O=5HCl+H3PO4

3)к сожалению не знаю

Объяснение:

Answer 2

Identification of the Unknown Element X

To identify the unknown element X, we can analyze the given information. The key characteristics of element X are as follows:

1. X is a chloride of an unknown element. 2. X is liquid at 20 degrees Celsius. 3. X reacts with water, producing white vapor. 4. The resulting solution of X and water has acidic properties.

Based on these characteristics, we can make the following determinations:

1. Subgroup of Element X: The unknown element X belongs to subgroup 2. (Source:

2. Reaction of X with Water: The reaction between element X and water can be represented as follows:

   X + H2O → HX + OH^-
   

This is a hydrolysis reaction, where X reacts with water to form an acid (HX) and a hydroxide ion (OH^-). (Source:

3. Nature of the White Vapor: The white vapor formed during the reaction of X with water is most likely hydrogen chloride (HCl) gas. When HCl gas comes into contact with moist air, it forms a white mist due to the reaction with water vapor in the air. (Source:

In summary, the unknown element X is a liquid chloride belonging to subgroup 2. It reacts with water in a hydrolysis reaction, forming an acid and a hydroxide ion. The white vapor produced during the reaction is likely hydrogen chloride gas.