Question

Сколько моль составляет, сколько молекул содержит и какой объем занимает 280 граммов азота N2 Нужно срочно И можно пожалуйста с Дано

Answer 1

Ответ:

10 моль, 60.2×10²³ молекул, 224 л.

Объяснение:

1)28 г - 1 моль

280 г - х моль.

x = (280×1)/28=10 моль.

2)1 моль - 6,02×10²³

10 моль - х

х=(10×6,02×10²³)/1=60,2×10²³

3)1 моль - 22,4 л

10 моль - х л.

х=(22,4×10)/1=224 л.

Не напиши скобки, я это написала просто, чтобы было ясно, что это дробь.

Лучший ответ, ПОЖАЛУЙСТА.

Answer 2

Given:

- Mass of nitrogen (N2): 280 grams

To find:

1. Number of moles of nitrogen (N2) 2. Number of molecules of nitrogen (N2) 3. Volume occupied by 280 grams of nitrogen (N2)

Solution:

1. Number of moles of nitrogen (N2): - To find the number of moles, we can use the formula: moles = mass / molar mass - The molar mass of nitrogen (N2) is 28 grams/mol. - Substituting the given values: moles = 280 grams / 28 grams/mol - Calculating the result: moles = 10 mol

2. Number of molecules of nitrogen (N2): - To find the number of molecules, we can use Avogadro's number, which states that 1 mole of any substance contains approximately 6.022 x 10^23 molecules. - Substituting the given value: molecules = moles x Avogadro's number - Calculating the result: molecules = 10 mol x 6.022 x 10^23 molecules/mol - Simplifying the result: molecules ≈ 6.022 x 10^24 molecules

3. Volume occupied by 280 grams of nitrogen (N2): - The volume of a gas can be calculated using the ideal gas law equation: V = (n x R x T) / P - Where: - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant (approximately 0.0821 L·atm/(mol·K)) - T is the temperature in Kelvin - P is the pressure in atmospheres - Since the pressure and temperature are not given, we cannot calculate the exact volume without this information.

Therefore, we have determined the following: - The mass of nitrogen (N2) is 280 grams. - The number of moles of nitrogen (N2) is 10 mol. - The number of molecules of nitrogen (N2) is approximately 6.022 x 10^24 molecules. - The volume occupied by 280 grams of nitrogen (N2) cannot be determined without the pressure and temperature information.

Please note that the volume calculation requires additional information to provide an accurate result.