Question

Для осуществления превращений в соответствии со схемой: Al(OH)3 → AlCl3 → Al(OH)3 необходимо последовательно использовать: 1) хлор и водород 2) хлорид натрия и гидроксид натрия 3) хлороводород и гидроксид натрия 4) соляную кислоту и калий пожалуйста помогите решить:​

Answer 1

Ответ:

3) хлороводород и гидроксид натрия

Объяснение:

Al(OH)3 + 3HCl = AlCl3 + 3H2O

AlCl3 + 3NaOH = Al(OH)3 + 3NaCl

Answer 2

The necessary reactions

For the conversions according to the scheme: Al(OH)3 → AlCl3 → Al(OH)3, it is necessary to use sequentially:

3) hydrochloric acid and sodium hydroxide

The reactions that must take place are:

1. Al(OH)3 + 3HCl → AlCl3 + 3H2O [[1]](https://omgtu.ru/general_information/institutes/petrochemical_institute/department_quot_technology_and_the_physics_of_low_temperatures_cryogenic/HTIB/uchebnoe%20obespechenie/%D0%92%D0%BE%D1%80%D0%BE%D0%BD%D0%BA%D0%BE%D0%B2%D0%B0,%20%D0%9D%D0%BE%D0%B2%D0%B3%D0%BE%D1%80%D0%BE%D0%B4%D1%86%D0%B5%D0%B2%D0%B0,%20%D0%9C%D0%B8%D1%80%D0%BE%D1%88%D0%BD%D0%B8%D1%87%D0%B5%D0%BD%D0%BA%D0%BE.%20%D0%9A%D0%B0%D1%87%D0%B5%D1%81%D1%82%D0%B2%D0%B5%D0%BD%D0%BD%D1%8B%D0%B5%20%D1%80%D0%B5%D0%B0%D0%BA%D1%86%D0%B8%D0%B8%20%D0%B2%20%D1%85%D0%B8%D0%BC%D0%B8%D0%B8.%20%D0%9F%D1%80._%D0%B8%D1%81%D0%BF.pdf) This reaction converts aluminum hydroxide to aluminum chloride using hydrochloric acid.

2. AlCl3 + 3NaOH → Al(OH)3 + 3NaCl This reaction converts aluminum chloride back to aluminum hydroxide using sodium hydroxide.

So the correct option is 3) hydrochloric acid and sodium hydroxide.

Hydrochloric acid is used to first convert aluminum hydroxide to aluminum chloride, then sodium hydroxide is used to convert the aluminum chloride back to aluminum hydroxide, completing the cycle. The other options would not produce the necessary reactions.