Question

Решите задачу. Бериллий нагрели с избытком фосфора. Получили 37 г продукта. Определите массу вступившего в реакцию металла.

Answer 1

Ответ: m(Be) = 15,56г

Х                     37г
5Be + 2P --> Be5P2
45г                  107г

Х = 37г * 45г / 107г = 15,56г

Объяснение:

Answer 2

Problem Analysis

To solve this problem, we need to determine the mass of the metal that reacted when beryllium was heated with an excess of phosphorus and produced 37 grams of product.

Solution

The reaction between beryllium and phosphorus can be represented by the following balanced chemical equation:

2Be + P4 -> 2BeP2

From the balanced equation, we can see that 2 moles of beryllium react with 1 mole of phosphorus to produce 2 moles of beryllium phosphide.

To find the mass of the metal that reacted, we can use the molar mass of beryllium (Be) and the molar mass of beryllium phosphide (BeP2).

The molar mass of beryllium (Be) is approximately 9.01 g/mol.

The molar mass of beryllium phosphide (BeP2) can be calculated by adding the molar masses of beryllium and phosphorus:

Molar mass of BeP2 = (2 * molar mass of Be) + (1 * molar mass of P) = (2 * 9.01 g/mol) + (1 * molar mass of P)

Unfortunately, we don't have the molar mass of phosphorus (P) in the given information. Therefore, we cannot calculate the exact mass of the metal that reacted without this information.

However, if we assume that the molar mass of phosphorus is approximately 31.0 g/mol, we can proceed with the calculation.

Using the assumed molar mass of phosphorus, we can calculate the molar mass of beryllium phosphide:

Molar mass of BeP2 = (2 * 9.01 g/mol) + (1 * 31.0 g/mol) = 49.02 g/mol

Now, we can use the molar mass of beryllium phosphide to calculate the mass of the metal that reacted:

Mass of metal = (Mass of BeP2 / Molar mass of BeP2) * Mass of BeP2 produced

Mass of metal = (37 g / 49.02 g/mol) * (2 * 9.01 g/mol) = (37 g / 49.02 g/mol) * 18.02 g

Calculating this expression will give us the mass of the metal that reacted.

Please note that the assumption made for the molar mass of phosphorus is an approximation, and the exact mass of the metal that reacted cannot be determined without the accurate molar mass of phosphorus.

Conclusion

Based on the given information, we cannot determine the exact mass of the metal that reacted when beryllium was heated with an excess of phosphorus and produced 37 grams of product. The calculation requires the accurate molar mass of phosphorus, which is not provided.