
Вычислить относительную молекулярную массу вещества Ca3(PO4)2 и массовые частицы элементов в ней.


Ответы на вопрос

Ответ:
Mr=310
W(Ca)=39%
W(P)=20%
W(O)=41%
Объяснение:



Calculation of the Relative Molecular Mass of Ca3(PO4)2
To calculate the relative molecular mass of Ca3(PO4)2, we need to determine the atomic masses of each element in the compound and multiply them by their respective subscripts.
The atomic masses of the elements involved are as follows: - Calcium (Ca): 40.08 g/mol - Phosphorus (P): 30.97 g/mol - Oxygen (O): 16.00 g/mol
The subscripts in the compound Ca3(PO4)2 indicate the number of atoms of each element present. Therefore, we have: - 3 atoms of calcium (Ca) - 2 atoms of phosphorus (P) - 8 atoms of oxygen (O)
To calculate the relative molecular mass, we multiply the atomic masses by their respective subscripts and sum them up:
Relative Molecular Mass of Ca3(PO4)2 = (3 * 40.08 g/mol) + (2 * 30.97 g/mol) + (8 * 16.00 g/mol)
Calculating this expression gives us the relative molecular mass of Ca3(PO4)2.
Mass Percentages of Elements in Ca3(PO4)2
To determine the mass percentages of the elements in Ca3(PO4)2, we need to calculate the mass of each element and divide it by the total mass of the compound.
1. Calcium (Ca): - Atomic mass: 40.08 g/mol - Number of atoms in Ca3(PO4)2: 3 - Mass of calcium in Ca3(PO4)2 = (3 * 40.08 g/mol)
2. Phosphorus (P): - Atomic mass: 30.97 g/mol - Number of atoms in Ca3(PO4)2: 2 - Mass of phosphorus in Ca3(PO4)2 = (2 * 30.97 g/mol)
3. Oxygen (O): - Atomic mass: 16.00 g/mol - Number of atoms in Ca3(PO4)2: 8 - Mass of oxygen in Ca3(PO4)2 = (8 * 16.00 g/mol)
To calculate the total mass of Ca3(PO4)2, we sum up the masses of each element.
Total mass of Ca3(PO4)2 = Mass of calcium + Mass of phosphorus + Mass of oxygen
Finally, we can calculate the mass percentages of each element by dividing the mass of each element by the total mass of Ca3(PO4)2 and multiplying by 100.
Note: The exact values for the relative molecular mass and mass percentages of Ca3(PO4)2 can be calculated using the atomic masses provided above.


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