Question

ДАЮ 50 БАЛЛОВ определите объём Углекислого газа образующегося при взаимодействии 20 г раствора серной кислоты с карбонатом кальция ( при этом ещё образуется сульфат кальция и вода)

Answer 1

CaCO3 + 2HCl = CaCl2 + CO2 + H2O
100 г/моль 22,4 л/моль

х = 20*22,4/100 = 4,48 л.
Ответ: 4,48 л.

Answer 2

Calculating the Volume of Carbon Dioxide Gas Produced

To calculate the volume of carbon dioxide gas produced when 20g of sulfuric acid solution reacts with calcium carbonate to produce calcium sulfate and water, we can use the stoichiometry of the balanced chemical equation for the reaction.

The balanced chemical equation for the reaction is: H2SO4 + CaCO3 → CaSO4 + CO2 + H2O

Step 1: Calculate the Moles of Sulfuric Acid

The first step is to calculate the moles of sulfuric acid (H2SO4) using its molar mass.

The molar mass of sulfuric acid (H2SO4) is 98.08 g/mol.

Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4 Moles of H2SO4 = 20g / 98.08 g/mol

Moles of H2SO4 ≈ 0.204 moles

Step 2: Determine the Stoichiometry of the Reaction

From the balanced chemical equation, we can see that 1 mole of sulfuric acid (H2SO4) reacts with 1 mole of calcium carbonate (CaCO3) to produce 1 mole of carbon dioxide (CO2).

Step 3: Calculate the Volume of Carbon Dioxide Gas

The ideal gas law can be used to calculate the volume of carbon dioxide gas produced. The ideal gas law is given by the equation: PV = nRT

Where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature

Assuming standard temperature and pressure (STP), which is 0°C (273.15 K) and 1 atm, the molar volume of an ideal gas at STP is 22.4 L/mol.

Volume of CO2 = Moles of CO2 * Molar volume at STP Volume of CO2 = 0.204 moles * 22.4 L/mol

Volume of CO2 ≈ 4.57 L

Therefore, the volume of carbon dioxide gas produced when 20g of sulfuric acid solution reacts with calcium carbonate is approximately 4.57 liters.