Question

Найти массу образовавшейся воды, если 4г оксида меди (ll) реагирует с водородом

Answer 1

Ответ:

n(CuO)=m(CuO):M(CuO)=4:80=0,05моль

CuO(0,05моль)+2H-->Cu+H2O(0,05моль)

n(H2O)=0,05моль

m(H2O)=n(H2O)×M(H2O)=0,05×18=0,9грамм

Ответ:0,9грамм

Answer 2

Calculating the Mass of Water Formed from the Reaction

To calculate the mass of water formed when 4g of copper (II) oxide reacts with hydrogen, we can use the chemical equation for the reaction and the molar masses of the substances involved.

The balanced chemical equation for the reaction is: CuO + H2 → Cu + H2O

From the given information, we know the mass of copper (II) oxide is 4g.

Now, let's calculate the mass of water formed.

Steps to Calculate the Mass of Water Formed:

1. Calculate the molar mass of CuO. 2. Use the molar ratio between CuO and H2O to find the moles of water formed. 3. Convert the moles of water to grams to find the mass of water formed.

Step 1: Calculate the Molar Mass of CuO

The molar mass of CuO can be calculated using the atomic masses of copper (Cu) and oxygen (O) from the periodic table.

The molar mass of CuO is: Cu: 63.55 g/mol O: 16.00 g/mol Molar mass of CuO = 63.55 g/mol + 16.00 g/mol = 79.55 g/mol.

Step 2: Use the Molar Ratio to Find Moles of Water Formed

From the balanced chemical equation, we know that 1 mole of CuO reacts with 1 mole of H2O.

Step 3: Convert Moles of Water to Grams

Now, we can use the molar mass of water (H2O) to convert moles of water to grams.

The molar mass of water (H2O) is: H: 1.01 g/mol O: 16.00 g/mol Molar mass of H2O = 1.01 g/mol + 16.00 g/mol = 18.02 g/mol.

Using the molar mass of water, we can calculate the mass of water formed.

Final Calculation:

Given that the molar mass of CuO is 79.55 g/mol and the molar mass of H2O is 18.02 g/mol, we can calculate the mass of water formed when 4g of CuO reacts with hydrogen.

4g of CuO is equivalent to: 4g / 79.55 g/mol = 0.0503 moles of CuO.

Since the molar ratio between CuO and H2O is 1:1, the moles of water formed will also be 0.0503 moles.

Converting moles of water to grams: 0.0503 moles * 18.02 g/mol = 0.906 g of water.

Answer:

The mass of water formed when 4g of copper (II) oxide reacts with hydrogen is approximately 0.906 grams.