
ПОЖАЛУЙСТА ПОМОГИТЕ УМОЛЯЯЮ ОЧЧЕНЬ НАДО ПОМОГИТЕ!! 1. ЗАПИШИТЕСЬ РЕАКЦИИ ГОРЕНИЯ ПРОПАНА И
ГЕКСАНА.2.ЗАПИШИТЕ ПОЭТАПНО ХЛОРИРОВАНИЕ МЕТАНА, НОЗОВИТЕ ПОЛУЧЕННЫЕ ПРОДУКТЫ.

Ответы на вопрос

Ответ:
1) C₃H₈ + 5O₂ = 3CO₂ + 4H₂O
2C₆H₁₄ + 19O₂ = 12CO₂ + 14H₂O
2) CH₄ + Cl₂ = CH₃Cl + HCl (хлорметан)
CH₃Cl + Cl₂ = CH₂Cl₂ + HCl (дихлорметан)
CH₂Cl₂ + Cl₂ = CHCl₃ + HCl (трихлорметан)
CHCl₃ + Cl₂ = CCl₄ + HCl (тетрахлорметан)
Объяснение:



Reactions of Propane and Hexane Combustion
The reactions of propane and hexane combustion can be described as follows:
Propane Combustion Reaction: The combustion of propane can be represented by the following chemical equation: ``` C3H8 + 5O2 → 3CO2 + 4H2O ``` This equation shows that when propane (C3H8) burns in the presence of oxygen (O2), it produces carbon dioxide (CO2) and water (H2O) as the main products [[1]].
Hexane Combustion Reaction: The combustion of hexane can be represented by the following chemical equation: ``` C6H14 + 9O2 → 6CO2 + 7H2O ``` This equation indicates that when hexane (C6H14) undergoes combustion with oxygen (O2), it yields carbon dioxide (CO2) and water (H2O) as the primary products [[2]].
Chlorination of Methane and Products Obtained
The chlorination of methane occurs through a series of steps and results in the formation of various products.
Stepwise Chlorination of Methane: 1. Initiation: The reaction is initiated by the homolytic cleavage of a chlorine molecule (Cl2) to form two chlorine radicals (Cl•). 2. Propagation: The chlorine radical (Cl•) reacts with methane (CH4) to form methyl radical (CH3•) and hydrogen chloride (HCl). The methyl radical then reacts with another chlorine molecule to form chloromethane (CH3Cl). 3. Termination: The process continues with the propagation steps until all the hydrogen atoms in methane are replaced by chlorine atoms.
Products Obtained from Chlorination of Methane: The products obtained from the chlorination of methane include chloromethane (CH3Cl), dichloromethane (CH2Cl2), chloroform (CHCl3), and carbon tetrachloride (CCl4) [[3]].
This process results in the gradual substitution of hydrogen atoms in methane with chlorine atoms, leading to the formation of a series of chlorinated products.
I hope this information helps! If you have any more questions or need further assistance, feel free to ask.


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