Question

Какую массу метанола сожгли, если в результате реакции выделилось 3 моль СО2?​

Answer 1

Ответ:

2CH3OH+3O2=2CO2+4H2O

1)Сначала найдем моли метанола:

при 2 молях метанола образовывается 2 моль СО2

при Х молях образовывается 3 моль СО2

Х=3

2)Рассчитаем массу метанола

m(масса метанола)=v(моль метанола)×Мr(молярная масса метанола)

v=3

Мr=32

m=?

m=3×32=96

Ответ:96

Answer 2

Calculating the Mass of Methanol Burned

To calculate the mass of methanol burned, we can use the information that 3 moles of CO2 were produced in the reaction. From this, we can determine the mass of methanol burned.

The balanced chemical equation for the combustion of methanol is: ``` 2CH3OH + 3O2 → 2CO2 + 4H2O ```

From the balanced equation, we can see that 2 moles of methanol produce 2 moles of CO2. Therefore, 1 mole of methanol produces 1 mole of CO2.

Using the molar mass of CO2 (44 g/mol), we can calculate the mass of methanol burned.

Step 1: Calculate the mass of 3 moles of CO2: ``` 3 moles of CO2 * 44 g/mol = 132 g ``` So, the mass of 3 moles of CO2 is 132 grams.

Step 2: Calculate the mass of methanol burned: Since 1 mole of methanol produces 1 mole of CO2, the mass of methanol burned is the same as the mass of CO2 produced.

Therefore, the mass of methanol burned is 132 grams.

This calculation is based on the stoichiometry of the balanced chemical equation for the combustion of methanol and the molar mass of CO2.

I hope this helps! If you have any further questions, feel free to ask.