Question

Какой объём водорода (н.у) выделяется при действии на цинк раствора соляной кислоты, содержащей 10,95 г хлороводорода? с надо и найти!!! дам 80 баллов !!!!!!

Answer 1

Составляем химическое уравнение, не забывая проставить коэффициенты: Zn + 2HCl = ZnCl2 + H2.
Найдём количество вещества HCl: n (HCl) = m / M = 10,95 / 36 = 0,3 моль.
Составляем пропорцию с помощью уравнения: n (HCl) / n (H2) = 2 / 1.
Найдём количество вещества водорода: n (H2) = n (HCl) / 2 = 0,3 / 2 = 0,15 моль.
Найдём объём водорода: V (H2) = n * Vm = 0,15 * 22,4 = 3,36л.
Ответ: V (H2) = 3,36л.

Answer 2

Calculating the Volume of Hydrogen Gas Produced

To calculate the volume of hydrogen gas (at standard temperature and pressure, STP) produced when zinc reacts with hydrochloric acid, we can use the stoichiometry of the balanced chemical equation for the reaction. The balanced chemical equation for the reaction between zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl2 + H2

According to the stoichiometry of the balanced chemical equation, 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Given that the hydrochloric acid contains 10.95 g of hydrogen chloride (HCl), we can calculate the moles of HCl and then use the stoichiometry to find the volume of hydrogen gas produced at STP.

Calculations

1. Calculate moles of HCl: - The molar mass of HCl is approximately 36.46 g/mol (1 g/mol for hydrogen + 35.46 g/mol for chlorine). - Moles of HCl = Mass of HCl / Molar mass of HCl - Moles of HCl = 10.95 g / 36.46 g/mol

2. Calculate moles of H2: - According to the stoichiometry of the balanced chemical equation, 2 moles of HCl produce 1 mole of H2. - Moles of H2 = Moles of HCl / 2

3. Calculate volume of H2 at STP: - 1 mole of any gas at STP occupies 22.4 liters. - Volume of H2 at STP = Moles of H2 * 22.4 L/mol

Result

The volume of hydrogen gas (at STP) produced when zinc reacts with the given amount of hydrochloric acid is approximately 0.301 liters.

Cited Sources

1. Source2. Source