Question

Оксид кальция массой 640 г нагрели с достаточным количеством оксида кремния(IV). Масса образовавшегося силиката кальция оказалась равной1024 г. Определите массовую долю выхода силиката кальция.

Answer 1

Ответ:

CaO + SiO₂ = CaSiO₃

n(CaO) = m/M = 640г/ 56г/моль = 11,43 моль

n(CaSiO₃) = n(CaO) = 11,43 моль (теоретически)

m(CaSiO₃) = n(CaSiO₃) * M(CaSiO₃)

m(CaSiO₃) = 11,43моль * 112г/моль = 1280,2г (теоретически)

выход(%) = (1024/12080,2) * 100%

выход = 84,75%

Объяснение:

Answer 2

Calculation of the Mass Fraction of Calcium Silicate

To determine the mass fraction of calcium silicate, we need to calculate the mass of calcium silicate formed and then divide it by the total mass of the reaction products.

Given: - Mass of calcium oxide (CaO) = 640 g - Mass of calcium silicate (CaSiO3) formed = 1024 g

To find the mass fraction of calcium silicate, we can use the formula:

Mass Fraction = Mass of Calcium Silicate / Total Mass of Reaction Products

Substituting the given values:

Mass Fraction = 1024 g / (640 g + 1024 g)

Calculating the sum in the denominator:

Mass Fraction = 1024 g / 1664 g

Simplifying the fraction:

Mass Fraction = 0.6154

Therefore, the mass fraction of calcium silicate is approximately 0.6154 or 61.54%.

Please note that the search results provided did not contain specific information related to the mass fraction of calcium silicate. The calculation above is based solely on the given information and does not rely on external sources.