Question

Допишіть праві частини рівняння А) H3PO4+KOH= В) K3PO4+AgNO3= Б) Mg3(PO4)2+H2SO4= Г) (NH4)2SO4=

Answer 1

H3PO4 + 3KOH => K3PO4 + 3H2O

K3PO4 + 3AgNO3 => 3KNO3 + Ag3PO4

Mg3(PO4)2 + 3H2SO4 => 3MgSO4 + 2H3PO4

3(NH4)2SO4 => N2 + 4HN3 + 6H2O + 3SO2

Или можно разложить по-другому:

(NH4)2SO4 => NH3 + NH4HSO4

Answer 2

A) H3PO4 + KOH =

The balanced equation for the reaction between phosphoric acid (H3PO4) and potassium hydroxide (KOH) is:

H3PO4 + 3KOH → K3PO4 + 3H2O [[1]]

In this reaction, one molecule of phosphoric acid reacts with three molecules of potassium hydroxide to produce one molecule of potassium phosphate (K3PO4) and three molecules of water (H2O).

B) K3PO4 + AgNO3 =

The balanced equation for the reaction between potassium phosphate (K3PO4) and silver nitrate (AgNO3) is:

3K3PO4 + 4AgNO3 → 12KNO3 + Ag3PO4 [[2]]

In this reaction, three molecules of potassium phosphate react with four molecules of silver nitrate to produce twelve molecules of potassium nitrate (KNO3) and one molecule of silver phosphate (Ag3PO4).

C) Mg3(PO4)2 + H2SO4 =

The balanced equation for the reaction between magnesium phosphate (Mg3(PO4)2) and sulfuric acid (H2SO4) is:

Mg3(PO4)2 + 3H2SO4 → 3MgSO4 + 2H3PO4 [[3]]

In this reaction, one molecule of magnesium phosphate reacts with three molecules of sulfuric acid to produce three molecules of magnesium sulfate (MgSO4) and two molecules of phosphoric acid (H3PO4).

Г) (NH4)2SO4 =

The given equation "(NH4)2SO4" is already balanced and does not require any additional components or modifications.

Ammonium sulfate ((NH4)2SO4) is a compound that consists of two ammonium ions (NH4+) and one sulfate ion (SO4^2-). It is commonly used as a fertilizer and in various industrial applications.

I hope this helps! Let me know if you have any further questions.