Question

ДАЮ 60 БАЛІВ! Здійсніть перетворення за поданими схемами: а) C CO2 H2CO3 CaCO3 в) Cu CuO CuSO4 Cu(OH)2 г) Na Na2O NaOH Na2SO4

Answer 1

a) C + O2 = CO2

CO2 + H2O = H2CO3

Ca(OH)2 + H2CO3 = CaCO3 + 2H2O

в) 2Cu + O2 = 2CuO

CuO + H2SO4 = CuSO4 + H2O

CuSO4 + 2NaOH = Cu(OH)2 + Na2SO4

г) 2Na + 2NaOH = 2Na2O + H2

Na2O + H2O = 2NaOH

2NaOH + H2SO4 = Na2SO4 + 2H2O

Answer 2

Chemical Reactions Transformation

a) C to CO2, H2CO3, CaCO3:

The transformation of C to CO2, H2CO3, and CaCO3 involves various chemical reactions. When carbon (C) reacts with oxygen (O2), it forms carbon dioxide (CO2). The reaction can be represented as:

C + O2 → CO2 [[1]]

Carbon dioxide (CO2) can further react with water (H2O) to form carbonic acid (H2CO3):

CO2 + H2O → H2CO3 [[2]]

Finally, carbonic acid (H2CO3) can decompose to form calcium carbonate (CaCO3) and water (H2O):

H2CO3 → CaCO3 + H2O [[3]]

b) Cu to CuO, CuSO4, Cu(OH)2:

The transformation of Cu to CuO, CuSO4, and Cu(OH)2 also involves several chemical reactions. When copper (Cu) reacts with oxygen (O2), it forms copper(II) oxide (CuO):

2Cu + O2 → 2CuO [[4]]

Copper(II) oxide (CuO) can then react with sulfuric acid (H2SO4) to form copper(II) sulfate (CuSO4) and water (H2O):

CuO + H2SO4 → CuSO4 + H2O [[5]]

Copper(II) hydroxide (Cu(OH)2) can be obtained by the reaction of copper(II) sulfate (CuSO4) with sodium hydroxide (NaOH):

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4 [[6]]

c) Na to Na2O, NaOH, Na2SO4:

The transformation of Na to Na2O, NaOH, and Na2SO4 involves the following chemical reactions. When sodium (Na) reacts with oxygen (O2), it forms sodium oxide (Na2O):

4Na + O2 → 2Na2O [[7]]

Sodium hydroxide (NaOH) can be obtained by the reaction of sodium (Na) with water (H2O):

2Na + 2H2O → 2NaOH + H2 [[8]]

Finally, sodium sulfate (Na2SO4) can be obtained by the reaction of sodium hydroxide (NaOH) with sulfuric acid (H2SO4):

2NaOH + H2SO4 → Na2SO4 + 2H2O [[9]]