Question

A) Ba(OH)2 + H2SO4 Б) AlCl3 + NaOH =хелп срочно ​

Answer 1

Ответ:Ba(OH)2 (aq) + H2SO4 (aq) → BaSO4 (s) + 2 H2O  AlCl3 + 3 NaOH → 3 NaCl + Al(OH)3

Объяснение:

Answer 2

A) Ba(OH)2 + H2SO4: The reaction between barium hydroxide (Ba(OH)2) and sulfuric acid (H2SO4) is a double displacement reaction, also known as a neutralization reaction. It can be represented by the following balanced chemical equation:

Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O

In this reaction, barium hydroxide reacts with sulfuric acid to form barium sulfate (BaSO4) and water (H2O). Barium sulfate is a white precipitate that is insoluble in water.

B) AlCl3 + NaOH: The reaction between aluminum chloride (AlCl3) and sodium hydroxide (NaOH) is a double displacement reaction, also known as a precipitation reaction. It can be represented by the following balanced chemical equation:

AlCl3 + 3NaOH -> Al(OH)3 + 3NaCl

In this reaction, aluminum chloride reacts with sodium hydroxide to form aluminum hydroxide (Al(OH)3) and sodium chloride (NaCl). Aluminum hydroxide is a white precipitate that can be formed in this reaction.

Note: It's always important to handle chemicals with caution and perform reactions in a controlled laboratory setting with appropriate safety measures.