Question

Sn->SnO->Sn(OH)2->SnSO4->SnCl2

Answer 1

2Sn + O2 = 2SnO

SnO + H2O = Sn(OH)2

Sn(OH)2 + H2SO4 = SnSO4 + 2H2O

SnSO4 + BaCl2 = SnCl2 + BaSO4

Answer 2

The sequence you provided represents a series of chemical reactions involving tin (Sn). Here's a breakdown of each step:

1. Sn → SnO: This reaction represents the oxidation of tin metal (Sn) to form tin(II) oxide (SnO) by reacting with oxygen. The balanced chemical equation for this reaction is: 2 Sn + O₂ → 2 SnO

2. SnO → Sn(OH)₂: Tin(II) oxide (SnO) reacts with water (H₂O) to form tin(II) hydroxide (Sn(OH)₂). The balanced chemical equation for this reaction is: SnO + 2 H₂O → Sn(OH)₂

3. Sn(OH)₂ → SnSO₄: Tin(II) hydroxide (Sn(OH)₂) can undergo a reaction with sulfuric acid (H₂SO₄) to form tin(II) sulfate (SnSO₄). The balanced chemical equation for this reaction is: Sn(OH)₂ + H₂SO₄ → SnSO₄ + 2 H₂O

4. SnSO₄ → SnCl₂: Tin(II) sulfate (SnSO₄) can be converted to tin(II) chloride (SnCl₂) by reacting with hydrochloric acid (HCl). The balanced chemical equation for this reaction is: SnSO₄ + 2 HCl → SnCl₂ + H₂SO₄

Each reaction in this sequence involves a chemical transformation of tin, resulting in different compounds. It's important to note that the sequence you provided is a simplified representation, and actual reaction conditions, stoichiometry, and catalysts may vary depending on the specific reaction setup.