Question

Помогите пожалуйста!1,5x(x+4)-x(7-0.5x)=0.5(10-2x)

Answer 1

файл

======================= 

Answer 2

1,5x(x+4)-x(7-0.5x)=0.5(10-2x)

1.5х^2+6x-7x+0,5x^2=5-1x

  1.5х^2+6x-7x+0,5x^2-5+1x=0

2x^2-5=0

2x^2=5

x^2=2,5 

x=-корен 10/2 

x= +корен 10/2

 

Answer 3

I can help you solve this equation. First, let's rewrite it in a more readable form:

$$1.5x(x+4)-x(7-0.5x)=0.5(10-2x)$$

Next, let's expand the brackets and simplify the terms:

$$1.5x^2+6x-7x+0.5x^2=5-x$$ $$2x^2-x-5=0$$

Now, we can use the quadratic formula to find the values of x that satisfy the equation:

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

In this case, $a=2$, $b=-1$, and $c=-5$. Plugging these values into the formula, we get:

$$x=\frac{1\pm\sqrt{1+40}}{4}$$ $$x=\frac{1\pm\sqrt{41}}{4}$$

These are the two possible solutions for x. To check our answer, we can substitute these values back into the original equation and see if they make it true. I hope this helps you understand how to solve this equation. If you have any other questions, feel free to ask me.Ответь+подробно.+Помогите+пожалуйста!1,5x(x+4)-x(7-0.5x)=0.5(10-2x)