Question

4y*2-4y+1 ---------------- 4y*2-1

Answer 1

Ответ:

Объяснение:

(4y² -4y +1) /( 4y² -1) = (2y -1)² /(2y - 1)(2y + 1) = (2y-1) /(2y + 1)

Answer 2

$\frac{4y^{2} -4y+1}{4y^{2}-1 } =$

$= \frac{(2y-1)^2}{(2y-1)(2y+1)} =$

$\frac{2y-1}{2y+1}$

Answer 3

To simplify the expression:

(4y^2 - 4y + 1) / (4y^2 - 1)

We can factor both the numerator and denominator to see if there are any common factors we can cancel out.

The numerator is a perfect square trinomial, so it can be factored as:

(2y - 1)^2

The denominator is the difference of squares, so it can be factored as:

(2y - 1)(2y + 1)

Now we can cancel out the common factor of (2y - 1) from the numerator and denominator:

(2y - 1)^2 / [(2y - 1)(2y + 1)]

(2y - 1) / (2y + 1)

Therefore, the simplified expression is:

(2y - 1) / (2y + 1)