Question

9^log9 16 + log5 125

Answer 1

9^log9 16 + log5 125=16+3=19
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a^log(a)b=b

Answer 2

To evaluate the expression, let's break it down step by step:

1. Evaluate the logarithms: log9 16 = log(16) / log(9) (using the change of base formula) log9 16 ≈ 1.2041

   log5 125 = log(125) / log(5) (using the change of base formula) log5 125 = 3 / log(5) ≈ 2.0959

2. Substitute the evaluated logarithms back into the expression: 9^(log9 16) + log5 125 9^1.2041 + 2.0959

3. Calculate the exponentiation and addition: 9^1.2041 ≈ 16.0002 16.0002 + 2.0959 ≈ 18.0961

Therefore, 9^log9 16 + log5 125 is approximately equal to 18.0961.