Question

(2x-3)(2x+3)-x^2=12x-69+3x^2

Answer 1

(2x-3)(2x+3)-x^2=12x-69+3x^2
4x^2-9-x^2=12x-69+3x^2
4x^2-9-x^2-12x+69-3x^2=0
-12x+60=0
12x=60
x=60/12
x=5
Ответ:х=5

Answer 2

Let's solve the equation step by step:

Expanding the left side of the equation: (2x - 3)(2x + 3) - x^2 = 12x - 69 + 3x^2

Using the FOIL method (First, Outer, Inner, Last) to expand the left side: (4x^2 - 9) - x^2 = 12x - 69 + 3x^2

Simplifying: 4x^2 - 9 - x^2 = 12x - 69 + 3x^2

Combining like terms: 3x^2 - 9 = 12x - 69 + 3x^2

The x^2 terms cancel out: -9 = 12x - 69

Rearranging the equation: 12x - 69 = -9

Adding 69 to both sides: 12x = 60

Dividing both sides by 12: x = 5

Therefore, the solution to the equation (2x - 3)(2x + 3) - x^2 = 12x - 69 + 3x^2 is x = 5.