Question

Брусок массой 2 кг находится на наклонной плоскости с углом наклона 30. Какую силу, направленную параллельно плоскости, надо приложить, чтобы удержать брусок в покое

Answer 1

При отсутствии трения F=m*g*sina=2*10*0,5=10 H

Answer 2

Calculating the Force Required to Keep the Block at Rest on an Inclined Plane

To calculate the force required to keep the 2 kg block at rest on the inclined plane with a 30-degree angle of inclination, we can use the following formula:

Force parallel to the plane (F) = Weight of the block (mg) * sin(θ)

Where: - m = mass of the block (2 kg) - g = acceleration due to gravity (approximately 9.81 m/s^2) - θ = angle of inclination (30 degrees)

Using this formula, we can calculate the force required to keep the block at rest on the inclined plane.

Calculation

The weight of the block (mg) = 2 kg * 9.81 m/s^2 = 19.62 N

Now, using the formula: F = 19.62 N * sin(30°)

Calculating the value of sin(30°): sin(30°) = 0.5

Substituting the value: F = 19.62 N * 0.5 = 9.81 N

Therefore, the force required to keep the 2 kg block at rest on the inclined plane with a 30-degree angle of inclination is 9.81 N.