Question

С трех лугов собрали 19,7 т сена. С первого и второго лугов собрали сена поровну, а с третьего собрали на 1,1 т  больше, чем с каждого из первых двух. Сколько сена собрали с каждого луга?

Answer 1

Problem Analysis

We are given that 19.7 tons of hay were collected from three meadows. The hay collected from the first and second meadows is equal, while the hay collected from the third meadow is 1.1 tons more than the hay collected from each of the first two meadows. We need to determine how much hay was collected from each meadow.

Solution

Let's assume that the amount of hay collected from each of the first two meadows is x tons. According to the problem, the amount of hay collected from the third meadow is 1.1 tons more than the amount collected from each of the first two meadows. Therefore, the amount of hay collected from the third meadow is x + 1.1 tons.

The total amount of hay collected from all three meadows is given as 19.7 tons. We can write this as an equation:

x + x + (x + 1.1) = 19.7

Simplifying the equation, we get:

3x + 1.1 = 19.7

Subtracting 1.1 from both sides of the equation, we have:

3x = 18.6

Dividing both sides of the equation by 3, we get:

x = 6.2

Therefore, the amount of hay collected from each of the first two meadows is 6.2 tons, and the amount of hay collected from the third meadow is 6.2 + 1.1 = 7.3 tons.

Answer

The amount of hay collected from each meadow is as follows: - First meadow: 6.2 tons - Second meadow: 6.2 tons - Third meadow: 7.3 tons

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