Question

На обработку одной детали первый рабочий затрачивает на 1 мин меньше, чем второй. Сколько деталей обработает каждый из них за 0,7 часа, если первый обрабатывает за это время на одну деталь больше чем второй?

Answer 1

Problem Analysis

We are given that the first worker takes 1 minute less than the second worker to process one part. We need to determine how many parts each worker will process in 0.7 hours (or 42 minutes) if the first worker processes one more part than the second worker in that time.

Solution

Let's assume that the second worker takes x minutes to process one part. Since the first worker takes 1 minute less than the second worker, the first worker takes (x - 1) minutes to process one part.

We can use the formula "time = (number of parts) * (time per part)" to calculate the number of parts processed by each worker.

For the first worker: - Time per part = (x - 1) minutes - Number of parts = ? (to be determined) - Time = 42 minutes

For the second worker: - Time per part = x minutes - Number of parts = ? (to be determined) - Time = 42 minutes

We can set up the following equations:

1. (x - 1) * (number of parts processed by the first worker) = 42 2. x * (number of parts processed by the second worker) = 42

To solve these equations, we can use substitution or elimination.

Let's solve the equations using substitution:

From equation 1, we can express the number of parts processed by the first worker in terms of x: (number of parts processed by the first worker) = 42 / (x - 1)

Substituting this expression into equation 2, we get: x * (42 / (x - 1)) = 42

Simplifying the equation: 42x = 42(x - 1) 42x = 42x - 42 42 = 42x - 42x 42 = -42

This equation has no solution, which means there is no valid value for x that satisfies the given conditions. Therefore, we cannot determine the number of parts processed by each worker in 0.7 hours based on the given information.

Conclusion: Based on the given information, it is not possible to determine the number of parts processed by each worker in 0.7 hours.