Question

Пожалуйста решите это срочно надо кто нибудь

Answer 1

1) $\frac{5}{9}+1 \frac{5}{7}*(4 \frac{2}{3}-2 \frac{5}{8}):1 \frac{3}{4}=\frac{5}{9}+\frac{12}{7}*(\frac{14}{3}-\frac{21}{8})*\frac{4}{7}=$$=\frac{5}{9}+\frac{12}{7}*\frac{14*8-21*3}{24}*\frac{4}{7}=\frac{5}{9}+\frac{12*49*4}{7*24*7}=\frac{5}{9}+2=2\frac{5}{9}=\frac{23}{9}$

2) $2-3\frac{1}{7}*(2-1\frac{9}{11})*\frac{21}{8}=2-\frac{22}{7}*(\frac{22}{11}-\frac{20}{11})*\frac{21}{8}=$$2-\frac{22*2*21}{7*11*8}=2-\frac{3}{2}=\frac{4}{2}-\frac{3}{2}=\frac{1}{2}=0,5$

3) $\frac{7}{3}+\frac{41}{10}:(\frac{37}{15}-\frac{5}{12})*\frac{5}{6}=\frac{7}{3}+\frac{41}{10}:(\frac{37*4}{60}-\frac{5*5}{60})*\frac{5}{6}=$$\frac{7}{3}+\frac{41}{10}:\frac{123}{60}*\frac{5}{6}=\frac{7}{3}+\frac{41*60*5}{10*123*6}=\frac{7}{3}+\frac{5}{3}=4$

4) $4\frac{5}{12}-1\frac{1}{12}:(2\frac{1}{6}+\frac{8}{15})*\frac{14}{15}=\frac{53}{12}-\frac{13}{12}:(\frac{13}{6}+\frac{8}{15})*\frac{14}{15}=$$\frac{53}{12}-\frac{13}{12}:\frac{13*5+8*2}{30}*\frac{14}{15}=\frac{53}{12}-\frac{13*30*14}{12*81*15}=\frac{53}{3*4}-\frac{13*7}{3*81}=\frac{53*81}{3*4*81}-\frac{13*7*4}{3*81*4}$$=\frac{4293-364}{972}=\frac{3929}{972}=4\frac{41}{972}$