Question

С железнодорожной станции в 12ч вышел скорый поезд со скоростью 70 км/ч. На 3 часа раньше с этой же станции в том же направлении вышел товарный поезд. в 16 часов скорый поезд догнал товарный. Найти скорость товарного поезда

Answer 1

     Ну раз скорый догнал товарный то расстояние они проехали равное:
х-скорость товарного поезда
                        Скорость(км/ч)     Время(ч)            Расстояние(км)
Товарный               х                         7                          280
Скорый                 70                         4                         280
280:7=40 (км/ч)-скорость товарного поезда

Answer 2

Problem Analysis

We are given that a fast train left a railway station at 12:00 with a speed of 70 km/h. Three hours earlier, a freight train left the same station in the same direction. At 16:00, the fast train caught up with the freight train. We need to find the speed of the freight train.

Solution

Let's assume the speed of the freight train is x km/h.

We know that the fast train traveled for 4 hours (from 12:00 to 16:00) and the freight train traveled for 7 hours (from 9:00 to 16:00).

Since distance = speed × time, we can set up the following equation:

70 km/h × 4 hours = x km/h × 7 hours

To find the value of x, we can solve this equation.

Calculation

Let's solve the equation to find the speed of the freight train:

70 km/h × 4 hours = x km/h × 7 hours

Simplifying the equation:

280 km = 7x

Dividing both sides of the equation by 7:

40 km = x

Therefore, the speed of the freight train is 40 km/h.

Answer

The speed of the freight train is 40 km/h.