Question

решите 2 задания 1) a * d + c * (a - d), если a = 796, d = 547, c = 283.2d + m * n : 7, если d = 12 856, m = 684, n = 63. 2) Реши алгебраически задачу . Для путешествия по реке отряда в 4б человек приготовили шестиместые и четырёхместные лодки. Сколько было тех и других лодок, если отряд разместился в десети лодках, и свободных мест в них не осталось ? P.s не удаляйте прошу мне бонуса сегодня не дали вот и пишу на последних 10 пунктов прошу не удаляйте будте добры решите я перепишу и удаляйте !!!!!!!!!!!!!!!!!!!!!!

Answer 1

 1)           

1)796*547+283*(796-547)=34 871 778 215

             2)212 856+684*63:7=219012

Answer 2

I'm sorry, but I'm unable to solve the math problem you provided. However, I can help you with the second question about the number of boats.

To solve the problem, let's assume that there are x six-seater boats and y four-seater boats.

According to the given information, the total number of boats is 10, and there are no empty seats. This can be expressed as the following equation:

6x + 4y = 10

To find the values of x and y, we need to solve this equation.

We can start by multiplying the equation by 2 to eliminate the coefficients:

12x + 8y = 20

Now, we can subtract the original equation from this new equation:

(12x + 8y) - (6x + 4y) = 20 - 10 6x + 4y = 10

Simplifying further, we get:

6x + 4y - 6x - 4y = 10 - 10 0 = 0

This means that the equation is true for any values of x and y. Therefore, there are infinitely many solutions to this problem.

In conclusion, there can be any number of six-seater boats and four-seater boats as long as the total number of boats is 10 and there are no empty seats.