
У ХОЗЯЙКИ ЕСТЬ РЫЧАЖНЫЕ ВЕСЫ И ГИРЯ В 100 ГРАММ КАК ЗА ТРИ ВЗВЕШИВАНИЯ ОНА МОЖЕТ ОТВЕСИТЬ 700 ГРАММ
КРУПЫ ?

Ответы на вопрос

2) Переложить 100 грамм к гире, взвесить ещё 200 грамм. (уже взвесили 100+200=300).
3) Переложить 200 грамм к гире и 100 граммам, взвесить ещё 400 грамм (итого 300+400=700).



This is a logical problem that can be solved by using the principle of division. Here is one possible way to answer it in detail:
- First, we need to divide the bulk of the groats into three equal parts, each weighing 300 grams. We can do this by using the scales and the 100-gram weight. We put the weight on one side of the scales and some groats on the other side until they balance. Then we repeat this process with the remaining groats until we have three balanced portions of 300 grams each. - Next, we need to take one of the 300-gram portions and divide it into two parts, one weighing 200 grams and the other weighing 100 grams. We can do this by using the scales and the 100-gram weight again. We put the weight on one side of the scales and some groats from the 300-gram portion on the other side until they balance. Then we have a 200-gram part and a 100-gram part. - Finally, we need to combine the 200-gram part with the 100-gram weight and the 100-gram part with another 300-gram portion. This way, we have two parts that weigh 300 grams each. We put them on the scales and they balance. Then we take one of them and add the remaining 300-gram portion to it. This way, we have a part that weighs 600 grams. We put it on one side of the scales and the 100-gram weight on the other side. They balance and we have 700 grams of groats.
This is one of the possible solutions to the problem. You can find more information and examples of similar problems on the following websites: [Uchi.ru](https://uchi.ru/otvety/questions/u-hozyayki-est-richazhnie-vesi-i-girya-v-100g-kak-za-tri-vzveshivaniya-ona-mozhet-otveset), [Infourok.ru](https://infourok.ru/zadachi-po-temam-princip-dirihle-vzveshivanie-logicheskie-zadachi-perelivaniya-5-6klass-5526613.html), and [NSPortal.ru](https://nsportal.ru/nachalnaya-shkola/matematika/2020/07/26/zadachnik-dlya-kursa-rnz-reshenie-nestandartnyh-zadach-3). I hope this helps you.


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