Question

Раскрыть скобки и решить : 1)(x+y-z)*3 2)4*(m-n-p) 3)-8*(a-b-c) 4)(2x-y+3)*(-2) 5)(3m-2n+p)*(-1) 6)(a+5-b-c)*mзарание спасибо

Answer 1

1)(x+y-z)*3=3(x+y-z)=3x+3y-3z
2)4(m-n-p)=4m-4n-4p
3)-8(a-b-c)=-8a+8b+8c
4)(2x-y+3)*(-2)=-2(2x-y+3)=-4x+2y-6
5)(3m-2n+p)*(-1)=-1(3m-2n+p)=-3m+2n-p
6)(a+5-b-c)*m=m(a+5-b-c)=am+5m-bm-cm

Answer 2

1)3х+3у-3z
2)4m-4n-4p
3)-8a+8b+8c
4)-4x+2y-6
5)-3m+2n-1p
6)am+5m-bm-cm

Answer 3

1) To solve the expression (x+y-z)*3+2, we can apply the distributive property of multiplication over addition/subtraction. This means we need to multiply each term inside the parentheses by 3 and then add 2 to the result.

So, (x+y-z)*3+2 = 3x + 3y - 3z + 2.

2) For the expression 4*(m-n-p)+3, we can again apply the distributive property. We multiply each term inside the parentheses by 4 and then add 3 to the result.

So, 4*(m-n-p)+3 = 4m - 4n - 4p + 3.

3) Moving on to the expression -8*(a-b-c)+4, we follow the same steps. Multiply each term inside the parentheses by -8 and then add 4 to the result.

So, -8*(a-b-c)+4 = -8a + 8b + 8c + 4.

4) For (2x-y+3)*(-2), we multiply each term inside the parentheses by -2.

So, (2x-y+3)*(-2) = -4x + 2y - 6.

5) Similarly, for (3m-2n+p)*(-1), we multiply each term inside the parentheses by -1.

So, (3m-2n+p)*(-1) = -3m + 2n - p.

6) Lastly, for (a+5-b-c)*m, we multiply each term inside the parentheses by m.

So, (a+5-b-c)*m = am + 5m - bm - cm.

Now we have simplified the given expressions.