Question

Прыжок зайца в 2 раза короче, но в 3 раза чаще, чем у волка. Кто быстрее преодолеет расстояние в 1 км? (подскажите решение, пожалуйста. Знаем, что заяц быстрее)

Answer 1

Через х давай , все получиться

Answer 2

Analysis and Solution

According to the given information, the hare's jump is twice as short as the wolf's jump, but the hare jumps three times more frequently than the wolf. We need to determine who will cover a distance of 1 km faster.

To solve this problem, we can assume that the wolf's jump distance is x units, and the hare's jump distance is x/2 units. We can also assume that the wolf takes n jumps to cover a distance of 1 km, and the hare takes 3n jumps to cover the same distance.

To find the time taken by each animal, we need to consider the distance covered in each jump and the number of jumps taken. Since the distance covered by each jump is different for the wolf and the hare, we need to calculate the total distance covered by each animal.

Let's calculate the distance covered by the wolf and the hare:

- Distance covered by the wolf = x * n - Distance covered by the hare = (x/2) * (3n)

To determine who covers the distance faster, we need to compare the total distances covered by each animal.

Now, let's compare the distances covered by the wolf and the hare:

- Distance covered by the wolf = x * n - Distance covered by the hare = (x/2) * (3n)

Since we know that the hare is faster, we can assume that the hare covers the distance in less time than the wolf. Therefore, we can set up the following inequality:

(x/2) * (3n) < x * n

Simplifying the inequality:

(3/2) * n < n

Since the number of jumps cannot be negative, we can cancel out n from both sides of the inequality:

(3/2) < 1

This inequality is not true, which means our assumption that the hare is faster is incorrect. Therefore, the wolf will cover the distance of 1 km faster than the hare.

Please note that the above solution is based on the given information and the assumption that the distance covered by each animal in each jump remains constant.