Question

Имеются 2 раствора соли в воде: первый-10%, а второй-30%. Смешали 140г первого раствора и 60г второго раствора. Сколько процентов составляет соль в полученном растворе?

Answer 1

10%=0,1
30%=0,3
140*0,1=14г соль из первого раствора
60*0,3=18г соль из второго раствора
14+18=32г всего соли в новом растворе
140+60=200г масса нового раствора
32:200*100%=16% соль в новом растворе

Answer 2

Calculation of the Percentage of Salt in the Mixture

To calculate the percentage of salt in the mixture, we need to consider the amounts of the two salt solutions that were mixed together.

Given: - First solution: 10% salt - Second solution: 30% salt - Amount of the first solution used: 140g - Amount of the second solution used: 60g

To find the percentage of salt in the resulting mixture, we can calculate the total amount of salt in the mixture and divide it by the total weight of the mixture.

Let's calculate the amount of salt in the mixture:

- Amount of salt from the first solution: 10% of 140g = 14g - Amount of salt from the second solution: 30% of 60g = 18g

The total amount of salt in the mixture is 14g + 18g = 32g.

Now, let's calculate the total weight of the mixture:

- Weight of the first solution used: 140g - Weight of the second solution used: 60g

The total weight of the mixture is 140g + 60g = 200g.

To find the percentage of salt in the mixture, we can divide the amount of salt in the mixture by the total weight of the mixture and multiply by 100:

Percentage of salt in the mixture = (32g / 200g) * 100 = 16%

Therefore, the percentage of salt in the resulting mixture is 16%.