
Решите пожайлуста систему 3x+4y=0 2x+3y=1 Все в 1 скобке


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System of Equations
To solve the system of equations 3x + 4y = 0 and 2x + 3y = 1, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the substitution method.
Substitution Method
1. Solve one equation for one variable in terms of the other variable. Let's solve the second equation for x: 2x + 3y = 1 Solving for x, we get: 2x = 1 - 3y x = (1 - 3y) / 2.
2. Substitute the expression for x into the other equation. Substituting x = (1 - 3y) / 2 into the first equation, we get: 3((1 - 3y) / 2) + 4y = 0 Simplifying the equation, we have: (3 - 9y) / 2 + 4y = 0 Multiplying both sides of the equation by 2 to eliminate the denominator, we get: 3 - 9y + 8y = 0 Combining like terms, we have: -y + 3 = 0 Solving for y, we get: y = 3.
3. Substitute the value of y back into one of the original equations to solve for x. Substituting y = 3 into the second equation, we get: 2x + 3(3) = 1 Simplifying the equation, we have: 2x + 9 = 1 Subtracting 9 from both sides of the equation, we get: 2x = -8 Dividing both sides of the equation by 2, we get: x = -4.
Therefore, the solution to the system of equations 3x + 4y = 0 and 2x + 3y = 1 is x = -4 and y = 3.


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