Question

Из города выехала машина со скоростью 60 километров в час .Одновременно с ней по тому же шоссе из города выехала легковая машина. Через 2 часа он обогнал грузовую на 40 километров с какой скоростью ехала легковая машина?

Answer 1

100 км/час двигалась легковая наверно:)

Answer 2

60*2=120 км за 2 часа проехала грузовая машина                                                   120+40=160 км проехала легковая машина                                                              160:2=80 км/час скорость легковой машины

Answer 3

Calculation of the Speed of the Passenger Car

To determine the speed at which the passenger car was traveling, we can use the information provided in the question.

The question states that a car left the city at a speed of 60 kilometers per hour. Simultaneously, another car on the same highway left the city as well. After 2 hours, the second car overtook a truck, which means it covered a distance of 40 kilometers more than the truck in those 2 hours.

To find the speed of the passenger car, we can set up the following equation:

Distance covered by the passenger car = Distance covered by the truck + 40 kilometers

Since the passenger car traveled for 2 hours at a constant speed, the distance covered by the passenger car can be calculated as:

Distance covered by the passenger car = Speed of the passenger car × Time

Substituting the given values, we have:

60 kilometers per hour × 2 hours = Speed of the passenger car × 2 hours + 40 kilometers

Simplifying the equation, we get:

120 kilometers = Speed of the passenger car × 2 hours + 40 kilometers

Rearranging the equation to solve for the speed of the passenger car, we have:

Speed of the passenger car × 2 hours = 120 kilometers - 40 kilometers

Speed of the passenger car × 2 hours = 80 kilometers

Dividing both sides of the equation by 2 hours, we find:

Speed of the passenger car = 80 kilometers / 2 hours

Therefore, the speed of the passenger car was 40 kilometers per hour.