Question

Саша и Петя одновременно поплыли навстречу друг другу от двух берегов пруда и через несколько минут встретились. Какое расстояние проплыл до встречи каждый из них,если расстояние между этими берегами пруда равно 300 м и один из пловцов проплыл на 120 м меньше другого?

Answer 1

1) 300 - 120 = 180(м) проплыли бы оба мальчика, если бы их скорость была
                                  одинакова.
2) 180 : 2 = 90(м) проплыл один из мальчиков
3) 90 + 120 = 210(м) проплыл второй из мальчиков
Ответ: 90м проплыл один мальчик, 210м проплыл другой.

Answer 2

Problem Analysis

We are given that Sasha and Petya are swimming towards each other from opposite sides of a pond. The distance between the two shores of the pond is 300 meters. It is also mentioned that one of the swimmers has swum 120 meters less than the other. We need to determine the distance each swimmer has swum before they meet.

Solution

Let's assume that Sasha has swum x meters. Since Petya has swum 120 meters less than Sasha, Petya has swum (x - 120) meters.

The total distance covered by both swimmers is equal to the distance between the shores of the pond, which is 300 meters. Therefore, we can write the equation:

x + (x - 120) = 300

Simplifying the equation:

2x - 120 = 300

Adding 120 to both sides:

2x = 420

Dividing both sides by 2:

x = 210

Therefore, Sasha has swum 210 meters, and Petya has swum (210 - 120) = 90 meters.

Answer

Sasha has swum 210 meters, and Petya has swum 90 meters before they meet.