Question

Из бака выходят 2 трубы . Через одну из них вытекает 4/5л воды в минуту , а через другую -в 1,5 раза больше . Полный бак опорожняется через обе трубы за 3 1/3 мин. Сколько литров воды вмещает бак

Answer 1

1) 4/5 · 1,5 = 4/5 · 3/2 = 1,2 (л/мин) - объем воды, вытекающей через вторую трубу в минуту.
2) 4/5 + 1,2 = 2 (л/мин)- объем воды, вытекающей через 2 трубы в минуту.
3) 2 · 3 1/3 = 2 · 10/3 = 20/3 = 6 2/3 (л)  - столько воды вмещает бак.

Answer 2

Problem Analysis

We are given that there are two pipes coming out of a tank. One pipe releases 4/5 liters of water per minute, while the other pipe releases 1.5 times more water. The tank is emptied through both pipes in 3 1/3 minutes. We need to determine the capacity of the tank.

Solution

Let's assume that the capacity of the tank is x liters.

According to the given information, the first pipe releases 4/5 liters of water per minute, and the second pipe releases 1.5 times more water. Therefore, the second pipe releases (4/5) * 1.5 = 6/5 liters of water per minute.

We are also given that the tank is emptied through both pipes in 3 1/3 minutes, which is equivalent to 10/3 minutes.

To find the capacity of the tank, we can set up the following equation:

x / (4/5) + x / (6/5) = 10/3

Simplifying the equation, we get:

(5x/4) + (5x/6) = 10/3

Multiplying through by the least common multiple (LCM) of the denominators, which is 12, we get:

3(5x) + 2(5x) = 40

Simplifying further, we have:

15x + 10x = 40

25x = 40

Dividing both sides by 25, we find:

x = 40/25

Simplifying, we get:

x = 8/5

Therefore, the capacity of the tank is 8/5 liters.

Answer

The tank can hold 8/5 liters of water.