Question

_РЕБББББЯЯЯЯТА!!!!!_______ПОМОГИТЕ РЕШИТЬНаша тема "Прямопропорциональные и обратнопропорциональные" И делаем решение задач с помощью пропорций.а) За 2,5 ч выпало 1,5 мм осадков. Сколько осадков выпало бы за 6 ч, если бы дождь шёл с такой же силой

Answer 1

2,5 ч -- 1,5 мм

6ч  ------ х мм

х=6*1,5/2,5

х= 3,6 мм

Ответ 3,6 мм 

Answer 2

2,5 ч   -  1,5 мм

 6 ч   -    х мм

здесь прямая пропорциональность

х=(6*1,5)/2,5=9/2,5=3,6 мм осадков выпало бы за 6 ч, если бы дождь шёл с такой же силой

Answer 3

Direct Proportions and Inverse Proportions

Direct proportions and inverse proportions are mathematical relationships between two variables. In a direct proportion, as one variable increases, the other variable also increases at a constant rate. In an inverse proportion, as one variable increases, the other variable decreases at a constant rate.

Problem: Rainfall Calculation

Let's solve the problem you provided using proportions. The problem states that in 2.5 hours, 1.5 mm of rainfall occurred. We need to find out how much rainfall would occur in 6 hours if the rain continued at the same intensity.

To solve this problem, we can set up a proportion using the given information. The proportion will relate the amount of rainfall to the time it takes for that amount to occur.

Let's assign variables to the given values: - Let x represent the amount of rainfall in 6 hours. - Let 2.5 represent the time in hours for 1.5 mm of rainfall.

Using the proportion, we can set up the equation:

2.5/1.5 = 6/x

To solve for x, we can cross-multiply and then divide:

2.5x = 1.5 * 6

2.5x = 9

x = 9/2.5

x = 3.6

Therefore, if the rain continued at the same intensity for 6 hours, approximately 3.6 mm of rainfall would occur.

Please note that this solution assumes a constant rate of rainfall throughout the entire period. In reality, rainfall intensity can vary, so this is an approximation based on the given information.

I hope this helps! Let me know if you have any further questions.