Question

А)Длина прямоугольника равна 12 м,а его ширина на 3 м меньше найди периметр и площадь прямоугольника.б)Площадь прямоугольника равна 80дм(в крадрате),а его ширина равна 5дм.На сколько надо уменьшить длину прямоугольника,чтобы его площадь уменьшилась на 35дм(в квадрате)?Ест ли лишнее данное в условии этой задачи?

Answer 1

А)ширина=12-3=9
P=12*2+9*2=42
S=12*9=108

Answer 2

Task A: Finding the perimeter and area of a rectangle

To find the perimeter and area of a rectangle, we need to know its length and width. Let's solve the problem step by step.

Given: - Length of the rectangle = 12 m - Width of the rectangle = 3 m less than the length

Step 1: Finding the width of the rectangle The width of the rectangle is given as 3 m less than the length. So, we can calculate the width by subtracting 3 m from the length: Width = Length - 3 m = 12 m - 3 m = 9 m

Step 2: Calculating the perimeter of the rectangle The perimeter of a rectangle is given by the formula: P = 2 * (Length + Width) Substituting the values, we get: P = 2 * (12 m + 9 m) = 2 * 21 m = 42 m

Step 3: Calculating the area of the rectangle The area of a rectangle is given by the formula: A = Length * Width Substituting the values, we get: A = 12 m * 9 m = 108 m²

Therefore, the perimeter of the rectangle is 42 m and the area is 108 m².