Question

Корова Мурка дает очень много молока - 50 литров в день. Матроскину надо разлить все молоко по трем бидонам, причем так, чтобы в первом бидоне было на 10 литров молока больше, чем во втором, а после переливания 26 литров из первого бидона в третий, в третьем бидоне стало столько же молока, сколько во втором. Сможет ли кот Матроскин разлить молоко таким образом? (Ответ обоснуйте).

Answer 1

х+у+z=50

x-10=y

z+26=y

x=y+10

z=y-26

y+10+y+y-26=50

3y=50-10+26=66

y=66/3=22

x=22+10=32

z=22-26=-4

Нельзя, так как в таком случае в третьем бидоне будет отрицательное количество молока

 

 

 

 

Answer 2

Problem Analysis

The problem states that a cow named Murka produces 50 liters of milk per day. Matroskin, a cat, needs to distribute all the milk into three containers (bidons) in such a way that the first bidon has 10 liters more milk than the second bidon. After pouring 26 liters from the first bidon into the third bidon, the amount of milk in the third bidon should be equal to the amount of milk in the second bidon. The question is whether Matroskin can distribute the milk in this way.

Solution

To solve this problem, we need to find a solution that satisfies all the given conditions. Let's break down the problem step by step:

1. The cow produces 50 liters of milk per day. 2. The first bidon should have 10 liters more milk than the second bidon. 3. After pouring 26 liters from the first bidon into the third bidon, the amount of milk in the third bidon should be equal to the amount of milk in the second bidon.

Let's assume the amount of milk in the second bidon is x liters. According to the given conditions, the first bidon should have x + 10 liters of milk. After pouring 26 liters from the first bidon into the third bidon, the third bidon should also have x liters of milk.

Now, let's write an equation to represent this situation:

(x + 10) - 26 = x

Simplifying the equation:

x + 10 - 26 = x

x - 16 = x

Subtracting x from both sides:

-16 = 0

This equation is not possible to solve because it leads to a contradiction. Therefore, it is not possible for Matroskin to distribute the milk in the specified way.

Conclusion

Based on the given conditions, Matroskin cannot distribute the milk in such a way that the first bidon has 10 liters more milk than the second bidon, and after pouring 26 liters from the first bidon into the third bidon, the third bidon has the same amount of milk as the second bidon. The equation derived from the conditions leads to a contradiction, indicating that the specified distribution is not possible.