Question

{3x-2y=4;{x+3y=5 ВОТ ЕЩЕ ОДНО ПОЖАЛУЙСТА СИСТЕМНОЕ

Answer 1

{3x-2y=4 
{х+3y=5⇒x=5-3y
теперь то что у нас получилось во втором подставляем в первое, получаем⇒3*(5-3y)-2y=4⇒15-9y-2y=4⇒-11y=-11 делим на минус 11 обе части, получаем y=1. Подставляем во второе и считаем x, x=5-3⇒x=2.
Ответ:y=1,x=2.

Answer 2

Solving the System of Equations

To solve the system of equations 3x - 2y = 4 and x + 3y = 5, we can use various methods such as substitution, elimination, or matrix methods. Let's solve it using the elimination method.

To eliminate one variable, we can multiply the first equation by 3 and the second equation by 2, so that the coefficients of y will cancel out when we add the equations together.

Multiplying the first equation by 3 gives us: 9x - 6y = 12.

Multiplying the second equation by 2 gives us: 2x + 6y = 10.

Adding the two equations together, we get: 11x = 22.

Dividing both sides of the equation by 11, we find: x = 2.

Now, we can substitute the value of x into one of the original equations to solve for y. Let's use the second equation:

Substituting x = 2 into x + 3y = 5, we get: 2 + 3y = 5.

Simplifying the equation, we find: 3y = 3.

Dividing both sides of the equation by 3, we find: y = 1.

Therefore, the solution to the system of equations 3x - 2y = 4 and x + 3y = 5 is x = 2 and y = 1.

Solution:

The solution to the system of equations is x = 2 and y = 1.