Question

Задача:В бассейн проведено 2 трубы.С помощью первой трубы бассейн может наполниться за 9 ч, а с помощью второй трубы вся вода из наполненного бассейна может вылиться за 6 ч. Как и на какую часть объема бассейна изменится уровень воды в нем за 1 час, если одновременно открыть обе трубы? Пожалуйста плиииз* Срочно надо

Answer 1

1) 1:4*2=1/2 бассейна заполнит первая труба за 2 часа

2) 1:6*2=1/3 бассейна заполнит вторая труба за 2 часа

3) 1/2+1/3=3/6+2/6=5/6 заполнят две трубы вместе за 2 часа

4) 1-5/6=1/6 бассейна останется незаполненной

Ответ: 1/6 бассейна 

 

Answer 2

Пояснение / - дробь

 Решение:

1 труба - 1/4 бассейна в час

2 труба - 1/6 бассейна

1) 1/4+1/6=3/12+2/12=5/12 (в 1 час)

2) 5/12*2=10/12=5/6 (обе трубы за 2 часа)

3) 1-5/6=1/6

Ответ: Не заполненной осталась 1/6 бассейна

Answer 3

Problem Analysis

We are given two pipes that can fill and drain a pool. The first pipe can fill the pool in 9 hours, while the second pipe can drain the entire pool in 6 hours. We need to determine how much the water level in the pool will change in 1 hour if both pipes are opened simultaneously.

Solution

To solve this problem, we need to calculate the net flow rate of water into or out of the pool when both pipes are open.

Let's assume the volume of the pool is represented by V.

The first pipe can fill the pool in 9 hours, so the rate at which it fills the pool is V/9 per hour.

The second pipe can drain the entire pool in 6 hours, so the rate at which it drains the pool is V/6 per hour.

When both pipes are open, the net flow rate of water into or out of the pool is the difference between the filling rate and draining rate.

Therefore, the net flow rate is V/9 - V/6 = V/18 - V/12 = -V/36 per hour. The negative sign indicates that the water level in the pool is decreasing.

To determine how much the water level in the pool will change in 1 hour, we need to calculate the fraction of the pool's volume that corresponds to the net flow rate of -V/36 per hour.

Let's represent the change in the water level in the pool in 1 hour as ΔV.

We can set up the following equation to solve for ΔV:

ΔV / V = -V/36

To isolate ΔV, we can multiply both sides of the equation by V:

ΔV = -V^2/36

Therefore, the water level in the pool will change by -V^2/36 in 1 hour when both pipes are open.

Answer

The water level in the pool will change by -V^2/36 in 1 hour when both pipes are open.

Please note that the negative sign indicates a decrease in the water level, and the value of V represents the volume of the pool.

Let me know if there's anything else I can help you with!